主题：【讨论】【跟进】趣味数学题 (三) -- 数值分析

if (st.k1) { //if first kid is selected and first kid is a boy
 if (st.k2) {// if second kid is a boy, increase the counter
 anotherKidIsBoyCount++;
 } 
 }
 else {
 if (st.k2) { // if 2nd kid is selected , and second it is a boy
 if (st.k1) { //if first kid is a boy, increase the counter
 anotherKidIsBoyCount++;
 }
 }
 }

这段代码有其实可以简化为

 if (st.k1 && st.k2) {
 anotherKidIsBoyCount++;
 }

我写得那么麻烦，存粹就是为了模拟见到第一个，检查第另一个孩子的场景。